The integral of y=3x^2 is:
∫y dx = ∫3x^2 dx
= 3 ∫x^2 dx
= 3 (x^3/3) + C, where C is the constant of integration.
Therefore, the integral of y=3x^2 is:
y = x^3 + C.
find the integral of the function y=3x^2
1 answer
1 answer