To find the initial value (b) of the linear function in the slope-intercept form \( y = mx + b \), we can use the given information:
- The slope \( m = -\frac{4}{7} \)
- The point \( (14, 3) \), meaning when \( x = 14 \), \( y = 3 \)
We can plug these values into the slope-intercept equation:
\[ 3 = -\frac{4}{7}(14) + b \]
Now, calculate \( -\frac{4}{7}(14) \):
\[ -\frac{4 \times 14}{7} = -\frac{56}{7} = -8 \]
Now substitute this back into the equation:
\[ 3 = -8 + b \]
To solve for \( b \), add 8 to both sides:
\[ b = 3 + 8 = 11 \]
Therefore, the initial value of the linear function is:
\[ \boxed{11} \]