To find the initial value \( b \) of the linear function, we can use the slope-intercept form of the equation of a line, which is given by:
\[ y = mx + b \]
where \( m \) is the rate of change (slope) and \( b \) is the y-intercept (initial value).
Given the slope \( m = -\frac{4}{7} \) and the point \( (14, 3) \), we can substitute these values into the equation to solve for \( b \).
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Substitute \( m \), \( x \), and \( y \) into the equation: \[ 3 = -\frac{4}{7}(14) + b \]
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Calculate \( -\frac{4}{7}(14) \): \[ -\frac{4 \times 14}{7} = -\frac{56}{7} = -8 \]
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Now, plug this back into the equation: \[ 3 = -8 + b \]
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Solve for \( b \): \[ b = 3 + 8 = 11 \]
So the initial value \( b \) is \( 11 \).
The correct response is:
b = 11.