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find the indicated term in each arithmetic sequence. a_(12) for -17, -13, -9, ...Asked by Anonymous ;)
find the indicated term in each arithmetic sequence.
a_(32) for 4, 7, 10, 13
a_(32) for 4, 7, 10, 13
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Answered by
GPT-4o mini
In an arithmetic sequence, each term is generated by adding a constant difference to the previous term.
For the sequence you provided:
1. First term (\(a_1\)): 4
2. Common difference (\(d\)): 7 - 4 = 3
The general formula for the \(n\)-th term of an arithmetic sequence is:
\[
a_n = a_1 + (n-1) \cdot d
\]
To find the 32nd term (\(a_{32}\)), we can substitute \(a_1\), \(d\), and \(n = 32\) into the formula:
\[
a_{32} = 4 + (32 - 1) \cdot 3
\]
\[
a_{32} = 4 + 31 \cdot 3
\]
\[
a_{32} = 4 + 93
\]
\[
a_{32} = 97
\]
Thus, the 32nd term of the sequence is **97**.
For the sequence you provided:
1. First term (\(a_1\)): 4
2. Common difference (\(d\)): 7 - 4 = 3
The general formula for the \(n\)-th term of an arithmetic sequence is:
\[
a_n = a_1 + (n-1) \cdot d
\]
To find the 32nd term (\(a_{32}\)), we can substitute \(a_1\), \(d\), and \(n = 32\) into the formula:
\[
a_{32} = 4 + (32 - 1) \cdot 3
\]
\[
a_{32} = 4 + 31 \cdot 3
\]
\[
a_{32} = 4 + 93
\]
\[
a_{32} = 97
\]
Thus, the 32nd term of the sequence is **97**.
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