To find the horizontal asymptote of the rational function \( f(x) = \frac{16x}{6x^2 + 1} \), we analyze the degrees of the polynomial in the numerator and the polynomial in the denominator.
- The degree of the numerator (which is \( 16x \)) is 1.
- The degree of the denominator (which is \( 6x^2 + 1 \)) is 2.
Since the degree of the numerator (1) is less than the degree of the denominator (2), the horizontal asymptote of the function is given by:
\[ y = 0 \]
Thus, the horizontal asymptote is:
A. The horizontal asymptote is \( y = 0 \).