Find the horizontal asymptote as ×-->8and describe what this mean in practical terms f(×)=150×+120/0.05×+1;the number of base ,f(×),after x months in a lake that was stocked with 120 bass

Answer 1

If you divide top and bottom by x, you have
f(x) = (150 + 120/x) / (.05 + 1/x)
As x gets huge, the fractions vanish, and
f(x) → 150/.05 = 3000
So, as time passes, the fish population stabilizes at 3000

Answer 2

so is this one of these answers; a. the number of bass, fx, after y months in a lake that was stocked by 130 bass. b. the number of bass, fx after x months in a lake that was stocked with 120 bass. c. the number of bass fx after x months in a lake was stocked with 140 bass. d. the number of bass fx after x months in a lake was stocked with 150 bass. i had b as my answer