find the height in feet of a ball after 6 seconds in the air. after one second the ball is 148 feet in the air; after 2 seconds it is 272 feet in the air

Answer 1

The height y(t) is given by
y(t) = h + vt - 16t^2
h + v - 16 = 148
h + 2v - 64 = 272
So,
h=-8
v=172

y(t) = -8 + 172t - 16t^2
y(6) = 448

Answer 2

You divide by 6 afterwards ??