Asked by liquidlew
Find the height, h, of the cylinder. The radius, r, is 5 cm and the diagonal, d
, is 15 cm. Round the answer to the nearest tenth.
(1 point)
Responses
15.8 cm
15.8 cm
11.2 cm
11.2 cm
18.0 cm
18.0 cm
14.1 cm
, is 15 cm. Round the answer to the nearest tenth.
(1 point)
Responses
15.8 cm
15.8 cm
11.2 cm
11.2 cm
18.0 cm
18.0 cm
14.1 cm
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the height \( h \) of the cylinder given the radius \( r = 5 \) cm and the diagonal \( d = 15 \) cm, we can use the Pythagorean theorem. The diagonal forms a right triangle with the height and the diameter of the base of the cylinder.
First, we need to find the diameter \( D \) of the cylinder:
\[
D = 2r = 2 \times 5 = 10 \text{ cm}
\]
Now, we can apply the Pythagorean theorem to the right triangle formed by the height \( h \), the radius (half of the diameter) \( r \), and the diagonal \( d \):
\[
d^2 = h^2 + r^2
\]
Substituting the values we have:
\[
15^2 = h^2 + 5^2
\]
\[
225 = h^2 + 25
\]
Now, we solve for \( h^2 \):
\[
h^2 = 225 - 25
\]
\[
h^2 = 200
\]
Taking the square root of both sides gives:
\[
h = \sqrt{200} \approx 14.1 \text{ cm}
\]
Rounding to the nearest tenth, the height \( h \) is approximately:
\[
h \approx 14.1 \text{ cm}
\]
Thus, the correct response is:
**14.1 cm**
First, we need to find the diameter \( D \) of the cylinder:
\[
D = 2r = 2 \times 5 = 10 \text{ cm}
\]
Now, we can apply the Pythagorean theorem to the right triangle formed by the height \( h \), the radius (half of the diameter) \( r \), and the diagonal \( d \):
\[
d^2 = h^2 + r^2
\]
Substituting the values we have:
\[
15^2 = h^2 + 5^2
\]
\[
225 = h^2 + 25
\]
Now, we solve for \( h^2 \):
\[
h^2 = 225 - 25
\]
\[
h^2 = 200
\]
Taking the square root of both sides gives:
\[
h = \sqrt{200} \approx 14.1 \text{ cm}
\]
Rounding to the nearest tenth, the height \( h \) is approximately:
\[
h \approx 14.1 \text{ cm}
\]
Thus, the correct response is:
**14.1 cm**
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