find the heat of reaction deltaT = -95.7KJ
2 Al2 O3(s) > 4Al (s) + 3 O2 (g)
a. - 95.7kj
b. +95.7kJ
c. -47.8 KJ
d. +47.8KJ
e. +191.4KJ
1 answer
Read and correct your post. Clarify. It makes no sense as is. delta T in kJ?
2 Al2 O3(s) > 4Al (s) + 3 O2 (g)
a. - 95.7kj
b. +95.7kJ
c. -47.8 KJ
d. +47.8KJ
e. +191.4KJ
1 answer
1 answer
1 answer
1 answer
2 answers