Find the gradient of the straight line that passes through the points (3,6) and (-5,-2) and hence find the equation of the line, clearly showing each step of your method

Answer 1

points (3,6) and (-5,-2)

Slope m = (y2 - y1)/(x2 - x1)
m = (-2 - 6)/(-5 - 3)
m = -8/-8 = 1

Slope-intercept form of the equation,
y = mx + b,
where m = slope and b = y-intercept

To find the y-intercept, Use either point to substitute into the equation,
y = mx + b

P (3,6), m = 1
y = mx + b
6 = 1(3) + b
6 = 3 + b
b = 3

Therefore, the equation where m = 1 and b = 3 is,
y = 1x + 3
y = x + 3

Answer 2

Thanks!

Answer 3

Thanks! I'm covering maths classes so it's annoying not knowing how to explain and mark work

we are trying to find out how to use the equation to determine whether or not the point (-3,2) lies on this line?

the x-intercept and the y-intercept of the line in the first question and the kids have to show each step of their method clearly.