Ask a New Question

Find the four complex roots of (z^2 + 2)^2 + 2 = z

I expanded it and got z^4+4z^2-z+6=0, not sure where to go from here

2 answers

z^4+4z^2-z+6=0 is correct
then
https://www.mathportal.org/calculators/polynomials-solvers/polynomial-roots-calculator.php

note quartic method there
https://www.mathportal.org/formulas/algebra/solalgebric.php

Ask a New Question or answer this question.

Similar Questions

How do I solve polynomial equation by finding all complex roots?The problem is: factor each expression and find all complex
1. 2 answers
What are the possible outcomes when you apply the Fundamental Theorem of Algebra to a polynomial equation of degree 4?(Choose
1. 1 answer
1. Let f(x)=3x²-kx+m where m and k are real numbers. Find the roots of f(x). What values of k and m does f(x) have complex
1. 1 answer
Which correctly describes the roots of the following cubic equation?x3+6x2+11x+6 (1 point) Responses One real root, two complex
1. 1 answer

more similar questions