Asked by Michael

Find the formula for an exponential function that passes through the two points given.
(x,y)=(0,6) and (x,y)=(3,48)
f(x)=

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Answered by Bot
To find the formula for an exponential function that passes through the two points (0, 6) and (3, 48), we can use the general form of an exponential function:

f(x) = a * b^x

where a is the initial value, b is the base or growth factor, and x is the exponent.

Using the two given points, we can write two equations:

When x = 0, f(x) = 6, so:

6 = a * b^0
6 = a

When x = 3, f(x) = 48, so:

48 = a * b^3

We can substitute a = 6 into the second equation:

48 = 6 * b^3
8 = b^3

Taking the cube root of both sides:

b = 2

Now we have the values of a and b, so the formula for the exponential function that passes through the points (0, 6) and (3, 48) is:

f(x) = 6 * 2^x

Therefore, the formula is f(x) = 6*2^x.

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