I suppose you are trying to find the integral:
I=∫2e^(2sqrt(y))/sqrt(y) dy
Use substitution
u=2sqrt(y)
du = dy/sqrt(y)
du = dy/sqrt(y)
I=∫2e^udu
=2e^u + C
=2e^(2sqrt(y)) + C
Find the following interval:
(2e^(2sqrt(y))/sqrt(y))
1 answer