Find the focus of the parabola defined by the equation
(
x
−
6
)
2
=
−
20
(
y
−
3
)
(x−6)
2
=−20(y−3).
Find the focus of the parabola defined by the equation
(
x
−
6
)
2
=
−
20
(
y
−
3
)
(x−6)
2
=−20(y−3).
2 answers
recall that the focus of
(x-h)^2 = 4p(y-k)
is at (h+p,k)
Now stop typing text vertically!!
(x-h)^2 = 4p(y-k)
is at (h+p,k)
Now stop typing text vertically!!