It probably looked like this
a1 = 6
an = -3an-1 - 12 , n≥2
So ...
a1 = 6
a2 = -3a1 - 12 = -3(6) - 12 = -30
a3 = -3a2 - 12 = -3(-30) - 12 = 78
carry on, only 2 more
Find the first five terms of the sequence in which a1 = 6 and an = –3an – 1 – 12, if n ≥ 2.
1 answer