To find the first five terms of the sequence defined by \( a_n = 6(8)^n \), we will substitute \( n \) with the values 1 through 5.
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For \( n = 1 \): \[ a_1 = 6(8)^1 = 6 \times 8 = 48 \]
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For \( n = 2 \): \[ a_2 = 6(8)^2 = 6 \times 64 = 384 \]
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For \( n = 3 \): \[ a_3 = 6(8)^3 = 6 \times 512 = 3072 \]
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For \( n = 4 \): \[ a_4 = 6(8)^4 = 6 \times 4096 = 24576 \]
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For \( n = 5 \): \[ a_5 = 6(8)^5 = 6 \times 32768 = 196608 \]
Thus, the first five terms of the sequence are:
- \( a_1 = 48 \)
- \( a_2 = 384 \)
- \( a_3 = 3072 \)
- \( a_4 = 24576 \)
- \( a_5 = 196608 \)
So, the final answer is: \[ { 48, 384, 3072, 24576, 196608 } \]