Asked by jarold
find the first derivative of the following functions:
y=[((x^2)-4)/(x+2)]
g(x)=[(x+1)/(x^1/2)]
Let's make like easier by doing some algebra first.
y=((x^2)-4)/(x+2) = x-2
dy/dx = 1
g(x)=[(x+1)/(x^1/2)]
= x^(1/2) - x^-1/2)
dg/dx = (1/2) x^-1/2 + (1/2)x^-3/2
y=[((x^2)-4)/(x+2)]
g(x)=[(x+1)/(x^1/2)]
Let's make like easier by doing some algebra first.
y=((x^2)-4)/(x+2) = x-2
dy/dx = 1
g(x)=[(x+1)/(x^1/2)]
= x^(1/2) - x^-1/2)
dg/dx = (1/2) x^-1/2 + (1/2)x^-3/2
Answers
There are no human answers yet.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.