The first Q1 would be ( 1+n)4 = which is the 25 % of the data set
and the Q3 would be n(3)/4 = the 75 % of the data :
So for Q1 its :
n= 10
(1+11)/4 = 3
The 3 is not the q1, this just tells where at what position the number is so the thirds number in the data set is 12, so therefore Q1= 12
find the first and third quartiles, Q1, and Q3, of the following numbers, 13,5,12,16,7,14,7,3,10,7
3 answers
corrections first put the numbers is order:
And Q3 is (n+1)3/4
3,5,7,7,7,10,12,13,14,16,
SO Q1= 7
and Q3= 12(3)/4 = 9
So the 9th number is 14 therefore Q3= 14
And Q3 is (n+1)3/4
3,5,7,7,7,10,12,13,14,16,
SO Q1= 7
and Q3= 12(3)/4 = 9
So the 9th number is 14 therefore Q3= 14
I am still not understanding how you came up with the answer, can you explain how to do it Thanks