Find the first and second derivatives of the given functions.

Question

y=¡î(x©÷+1)
y'=x(x©÷+1)^(-1/2)
y"=[1(x©÷+1)^(-1/2)]-[(1/2)[(x©÷+1)^(-3/2)](2x)(x)]
y"=[(x©÷+1)^(-1/2)]-[(x©÷)(x©÷+1)^(-3/2)]

Is the second derivative right?

Answer 1

y=root(x^2+1)
y'=x(x^2+1)^(-1/2)
y"=[1(x^2+1)^(-1/2)]-[(1/2)[(x^2+1)^(-3/2)](2x)(x)]
y"=[(x^2+1)^(-1/2)]-[(x^2)(x^2+1)^(-3/2)]

Answer 2

I agree