Asked by Brock


Find the first 4 terms and the 8th term of the recursively-defined sequence.

b1 = 2 and bk+1 = 3bk, for k>0

A. 6, 18, 54, 162; 13,122
B. 3, 6, 9, 12; 24
C. 5, 8, 11, 14; 26
D. 6, 12, 24, 48; 768
E. 2, 6, 18, 54; 4374
F. 2, 4, 8, 16; 256

Thanks!

Answered by Steve
each term will just be 2 times a power of 3, starting with 2*3^0. So, (E)
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