Find the expression that is equivalent to 3𝑥2+2𝑥−5𝑥−2𝑥2+2 (𝑥−2)(𝑥−1) (𝑥+2)(𝑥−2) (𝑥+1)(𝑥+2)

1 answer

To simplify the given expression \( \frac{3x^2 + 2x - 5x - 2x^2 + 2}{(x - 2)(x - 1)(x + 2)(x - 2)(x + 1)(x + 2)} \), we first need to simplify the numerator and the denominator.

Step 1: Simplify the Numerator

Start with the expression in the numerator:

\[ 3x^2 + 2x - 5x - 2x^2 + 2 \]

Combine like terms:

\[ (3x^2 - 2x^2) + (2x - 5x) + 2 \]

This results in:

\[ x^2 - 3x + 2 \]

Step 2: Factor the Numerator

Now, we will factor \( x^2 - 3x + 2 \):

\[ x^2 - 3x + 2 = (x - 1)(x - 2) \]

Step 3: Simplify the Denominator

Now, let's look at the denominator:

\[ (x - 2)(x - 1)(x + 2)(x - 2)(x + 1)(x + 2) = (x - 2)^2(x - 1)(x + 2)^2(x + 1) \]

Step 4: Rewrite the Complete Expression

Now substituting in the factored numerator gives:

\[ \frac{(x - 1)(x - 2)}{(x - 2)^2(x - 1)(x + 2)^2(x + 1)} \]

Step 5: Cancel Common Factors

In this expression, we can cancel out \( (x - 1) \) and one \( (x - 2) \):

\[ \frac{\cancel{(x - 1)} (x - 2)}{(x - 2) \cancel{(x - 1)} (x + 2)^2 (x + 1)} = \frac{1}{(x - 2)(x + 2)^2(x + 1)} \]

Final Result:

Thus, the expression that is equivalent to the given one is:

\[ \boxed{\frac{1}{(x - 2)(x + 2)^2(x + 1)}} \]