Find the exponential equation for the sequence: (0,4),(1,7.6),(2,14.44)…

y = ?(?)^x

1 answer

To find the exponential equation of the given sequence (0, 4), (1, 7.6), (2, 14.44), we'll use the general form of an exponential function, which is:

\[ y = a \cdot b^x \]

where \( a \) is the initial value when \( x = 0 \), and \( b \) is the growth factor.

  1. Find \( a \): From the first point (0, 4), we can see that when \( x = 0 \):

    \[ y = a \cdot b^0 = a \]

    Thus, \( a = 4 \).

  2. Use another point to find \( b \): Now we'll use the point (1, 7.6) to find \( b \):

    \[ 7.6 = 4 \cdot b^1 \] \[ b = \frac{7.6}{4} = 1.9 \]

  3. Check with the next point (2, 14.44): Now we will check whether this value of \( b \) works with the third point (2, 14.44):

    \[ y = 4 \cdot (1.9)^2 \] \[ y = 4 \cdot 3.61 = 14.44 \]

    This matches the third point perfectly.

Thus, the exponential equation for the sequence is:

\[ y = 4 \cdot (1.9)^x \]