well, the points give you the opposite side, and the adjacent side. The hypotenuse must then be sqrt (25+16). So now one knows all three sides.
Use the formulas for sine, cosine, and tangent, then invert them for the other three.
Find the exact values of the six trigonometric functions of theta if the terminal side of theta in standard position contains the point (-5/-4)
3 answers
so R would be sqrt41 and then sin=-4/sqrt41 cos=-5/sqrt41 and so on and so forth right?
The values of the six trig. functions should be:
sin(theta) = -4
-------
sqrt(41)
cos(theta) = -5
-------
sqrt(41)
tang(theta) = 4/5
csc(theta = sqrt(41)
--------
-4
sec(theta) = sqrt(41)
--------
-5
cot(theta)= 5/4
sin(theta) = -4
-------
sqrt(41)
cos(theta) = -5
-------
sqrt(41)
tang(theta) = 4/5
csc(theta = sqrt(41)
--------
-4
sec(theta) = sqrt(41)
--------
-5
cot(theta)= 5/4