Find the exact value of the sine, cosine, and tangent of the angle 330 degrees.

Question

I know the tangent is -(square root 3)/3, but how?

Answer 1

330 ° = 360 ° - 30 °

Circular functions:

sin ( 360 ° - theta ) = - sin theta

sin 330 ° = sin ( 360 ° - 30 ° ) = - sin 30 ° = - 1 / 2

cos ( 360 ° - theta ) = cos theta

cos 330 ° = cos ( 360 ° - 30 ° ) = cos 30 ° = sqroot 2 / 2

tan ( 360 ° - theta ) = - tan theta

tan 330 ° = tan( 360 ° - 30 ° ) = - tan 30 ° = - sqroot 3 / 3