Use the quadratic formula
x = [-b +/- sqrt(b^2-4ac)]/2a
if you do not see how to factor it.
Note that b^2-4ac = 1, so there are real solutions.
This is not a calculus question. it is algebra.
Find the exact real solutions, if any, of this quadratic equation. Use any method. If there is no real solution enter NONE in each box.
2x^2-5x+3=0
Is the smaller value none andthe larger value none.
1 answer