Find the exact area of the region that lies beneath the curve y = 3(x^[1/3]) 0 ≤ x ≤ 27

Answer 1

that would, of course, be
∫[0,27] 3x^(1/3) dx

Answer 2

find the exact area of the region that lies beneath the curve y=6cubesqrtx 0≤x≤27