LOL you can do this one, i just did the trapezoid
here
1_ 4_ _2_ _4__ 2_ _4_ _2__ 4_ 1
* values of (1+x^3)^.5 at
0 1/8 1/4 3/8 1/2 5/8 3/4 7/8 1
You will find those y values at the trapezoid problem that I already did
and use (1/8)/3 = 1/24 times sum
I am a Naval Architect. I wish I had seen this before the trapezoid one. We use Simpsons for everything because ship curves tend to be sort of parabolic.
Find the Error resulted from approximation by Simpson's Rule:
integral (from 0 to 1) sqrt( 1+x^3) dx
... compute the result for n=8
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