no figure. But, you know that if R1 and R2 are in series, then
R = R1 + R2
If they are in parallel, then
1/R = 1/R1 + 1/R2
Find the equivalent resistance of the combination of resistors shown in the figure below.
R1=1.52 microohms
R2= 21.1microohms
3 answers
www.webassign.net/webassignalgphys1/21-p-008.gif
so plug in your numbers and resolve each branch.
For example, on the right side, the .75 in || with 21.1 = 0.72
So now you have 1.5 in series with 0.72, so that's like a 2.22 resistor there.
Now work through the branch on the left, and you will be left with three resistances in parallel, so just apply the parallel R formula for three values.
For example, on the right side, the .75 in || with 21.1 = 0.72
So now you have 1.5 in series with 0.72, so that's like a 2.22 resistor there.
Now work through the branch on the left, and you will be left with three resistances in parallel, so just apply the parallel R formula for three values.