Find the equation of the tangent to the curve y=1/2x^2-4x-3at the point where the curve intersects the y-axis.

Answer 1

I have now done 2 of your quite straightforward questions. You MUST know how to do these type of relatively easy Calculus problems.
Show me the steps of your solution so I can check it.

Answer 2

I'll help you with the calculus:

y'(x) = x-4

The rest is just Algebra I.