Find the equation of the tangent line to the graph of y=3cot^4x at x=pi/4

Question

3cot^4(pi/4)=3(1)=3

Answer 1

(pi/4,3)=(x,y)

d/dx 3cot^4x= 12cot^3x
d/dx cotx= -csc^x
d/dx x=1

(12cot^3x)(-csc^2x)(1)

m=-12cot^3xcsc^2x

equation to the tangent line would be

y-3=-12cot^3xcsc^2x(x-pi/4) ?

Answer 2

pretty good, but you know that
cot π/4 = 1
csc π/4 = √2, so
m = -12(1)(2) = -24

So the line is

y-3 = -24(x-π/4)

Answer 3

okay, I forgot to break down the equation, thank you.