Find the equation of the tangent line to the curve y=e^2x + 4x at the point (0,1)

Answer 1

dy/dx = 2 e^(2x) + 4

at the point (0,1)
dy/dx = 2e^0 + 4
= 6

y = 6x + 1

since (0,1) is the y-intercept we can just state the answer.

btw, one would expect a student to correctly spell the subject he/she is studying.