Find the equation of the normal to the curve y=x^2-x-2 at the point where the curve meet the line y=x+1

Answer 1

The curves meet at (-1,0) and (3,4)
y' = 2x-1
at (-1,0) y' = -1
so the normal has a slope of 1
That makes the equation of the normal
y-0 = 1(x+1)

Now do the other point in like wise