y=mx+b
5=m(-2)+b
-3=m(-6)+b
divide the second equation by -3
then add the equations. That gives you b.
then go back to either equation to solve for m.
Find the equation of the line that passes through (-2,5) and (-6,-3)
3 answers
can you show me them
thats part of algebra 2 that's easy were doing that now in pre algebra