Find the equation of the line that is the image set of the flattening,

f(x,y)=(3x-3y, x-y)

3 answers

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well, if u = x-y

v(u) = u/3
Remember that f(1,0)=(a,c) and f(0,1)=(b,d) so plug the values of x and y f(0,1) or f(1,0) into the function to find the values for a,c or b,d.

Once you have values for x' and y' under the function then you can plug these values into the equation of a line to find the gardient which will give you the equation of the line.