To find the equation of the line that is parallel to \( y = \frac{2}{5}x + 1 \) and passes through the point \( (5, 5) \), we first note that parallel lines have the same slope.
The slope of the given line \( y = \frac{2}{5}x + 1 \) is \( \frac{2}{5} \). Therefore, the slope of the line we want to find will also be \( \frac{2}{5} \).
Next, we can use the point-slope form of the equation of a line, which is given by:
\[ y - y_1 = m(x - x_1) \]
where \( m \) is the slope, and \( (x_1, y_1) \) is the point through which the line passes.
In our case:
- \( m = \frac{2}{5} \)
- \( (x_1, y_1) = (5, 5) \)
Substituting these values into the point-slope form:
\[ y - 5 = \frac{2}{5}(x - 5) \]
Now, we can simplify this equation.
First, distribute \( \frac{2}{5} \):
\[ y - 5 = \frac{2}{5}x - \frac{2}{5} \cdot 5 \]
\[ y - 5 = \frac{2}{5}x - 2 \]
Next, add 5 to both sides:
\[ y = \frac{2}{5}x - 2 + 5 \]
Simplifying further:
\[ y = \frac{2}{5}x + 3 \]
Thus, the equation of the line that is parallel to \( y = \frac{2}{5}x + 1 \) and passes through the point \( (5, 5) \) is:
\[ y = \frac{2}{5}x + 3 \]
So, filling in the blank, you get:
The line that is parallel to \( y = \frac{2}{5}x + 1 \) and passes through the point \( (5,5) \) is \( y = \frac{2}{5}x + 3 \).