Find the equation of the line that is parallel to the line y=2/5x+1

and passes through the point (5,5)
.(1 point)
The line that is parallel to y=2/5x+1
and passes through the point (5,5)
is y=2/5x+

11 answers

To find the equation of the line that is parallel to \( y = \frac{2}{5}x + 1 \) and passes through the point \( (5, 5) \), we first note that parallel lines have the same slope.

The slope of the given line \( y = \frac{2}{5}x + 1 \) is \( \frac{2}{5} \). Therefore, the slope of the line we want to find will also be \( \frac{2}{5} \).

Next, we can use the point-slope form of the equation of a line, which is given by:

\[ y - y_1 = m(x - x_1) \]

where \( m \) is the slope, and \( (x_1, y_1) \) is the point through which the line passes.

In our case:

  • \( m = \frac{2}{5} \)
  • \( (x_1, y_1) = (5, 5) \)

Substituting these values into the point-slope form:

\[ y - 5 = \frac{2}{5}(x - 5) \]

Now, we can simplify this equation.

First, distribute \( \frac{2}{5} \):

\[ y - 5 = \frac{2}{5}x - \frac{2}{5} \cdot 5 \]

\[ y - 5 = \frac{2}{5}x - 2 \]

Next, add 5 to both sides:

\[ y = \frac{2}{5}x - 2 + 5 \]

Simplifying further:

\[ y = \frac{2}{5}x + 3 \]

Thus, the equation of the line that is parallel to \( y = \frac{2}{5}x + 1 \) and passes through the point \( (5, 5) \) is:

\[ y = \frac{2}{5}x + 3 \]

So, filling in the blank, you get:

The line that is parallel to \( y = \frac{2}{5}x + 1 \) and passes through the point \( (5,5) \) is \( y = \frac{2}{5}x + 3 \).

What value completes the equation of the line that is perpendicular to the line y=−3/4x+7
and goes through the point (6,1)
?(1 point)
The line that is perpendicular to y=−3/4x+7
and passes through the point (6,1)
is y=4/3x+

To find the equation of a line that is perpendicular to the line given by \( y = -\frac{3}{4}x + 7 \) and passes through the point \( (6, 1) \), we first need to determine the slope of the perpendicular line.

  1. Identify the slope of the original line: The slope of the line \( y = -\frac{3}{4}x + 7 \) is \( -\frac{3}{4} \).

  2. Find the slope of the perpendicular line: The slope of a line that is perpendicular to another is the negative reciprocal of the original slope. Therefore, the slope \( m \) of the perpendicular line is: \[ m = -\frac{1}{\left(-\frac{3}{4}\right)} = \frac{4}{3} \]

  3. Use the point-slope form: Now we can use the point-slope form of the equation of a line, which is given by: \[ y - y_1 = m(x - x_1) \] where \( (x_1, y_1) \) is the point through which the line passes, and \( m \) is the slope.

    Plugging in our values:

    • \( m = \frac{4}{3} \)
    • \( (x_1, y_1) = (6, 1) \)

    We get: \[ y - 1 = \frac{4}{3}(x - 6) \]

  4. Simplify the equation: Distributing \( \frac{4}{3} \): \[ y - 1 = \frac{4}{3}x - \frac{4}{3} \cdot 6 \] \[ y - 1 = \frac{4}{3}x - 8 \]

    Now, add 1 to both sides: \[ y = \frac{4}{3}x - 8 + 1 \] \[ y = \frac{4}{3}x - 7 \]

So the value that completes the equation of the line that is perpendicular to \( y = -\frac{3}{4}x + 7 \) and passes through the point \( (6, 1) \) is:

The line that is perpendicular to \( y = -\frac{3}{4}x + 7 \) and passes through the point \( (6,1) \) is \( y = \frac{4}{3}x - 7 \).

Therefore, filling in the blank, we have:

The line that is perpendicular to \( y = -\frac{3}{4}x + 7 \) and passes through the point \( (6, 1) \) is \( y = \frac{4}{3}x - 7 \).

Which of the following lines would be parallel to y=3/4x−2 ?(1 point)
Responses

4x−3y=12
4 x minus 3 y equals 12

3x−4y=8
3 x minus 4 y equals 8

3x−4y=12
3 x minus 4 y equals 12

4x−3y=6

To determine which of the lines is parallel to \( y = \frac{3}{4}x - 2 \), we need to find the slope of the given line and then compare it with the slopes of the lines provided in the responses.

The slope of the line \( y = \frac{3}{4}x - 2 \) is \( \frac{3}{4} \). For a line to be parallel, it must have the same slope.

Now, let's find the slope of each of the given lines by rewriting them in slope-intercept form \( y = mx + b \) (where \( m \) is the slope).

  1. \( 4x - 3y = 12 \): \[ -3y = -4x + 12 \quad \Rightarrow \quad y = \frac{4}{3}x - 4 \] Slope: \( \frac{4}{3} \)

  2. \( 3x - 4y = 8 \): \[ -4y = -3x + 8 \quad \Rightarrow \quad y = \frac{3}{4}x - 2 \] Slope: \( \frac{3}{4} \)

  3. \( 3x - 4y = 12 \): \[ -4y = -3x + 12 \quad \Rightarrow \quad y = \frac{3}{4}x - 3 \] Slope: \( \frac{3}{4} \)

  4. \( 4x - 3y = 6 \): \[ -3y = -4x + 6 \quad \Rightarrow \quad y = \frac{4}{3}x - 2 \] Slope: \( \frac{4}{3} \)

Now that we have calculated the slopes:

  • The slope of \( 4x - 3y = 12 \) is \( \frac{4}{3} \) (not parallel).
  • The slope of \( 3x - 4y = 8 \) is \( \frac{3}{4} \) (parallel).
  • The slope of \( 3x - 4y = 12 \) is \( \frac{3}{4} \) (parallel).
  • The slope of \( 4x - 3y = 6 \) is \( \frac{4}{3} \) (not parallel).

Conclusion: The lines \( 3x - 4y = 8 \) and \( 3x - 4y = 12 \) are parallel to \( y = \frac{3}{4}x - 2 \).

just pick 1

The line that is parallel to \( y = \frac{3}{4}x - 2 \) is:

\( 3x - 4y = 8 \).

Which line is parallel to the line y=5/6x and goes through the point (12,6)?(1 point)
Responses

6y=5x
6 y equals 5 x

y=5/6x−4
y equals Start Fraction 5 over 6 End Fraction x minus 4

y=5/6x+6
y equals Start Fraction 5 over 6 End Fraction x plus 6

y=−6/5x+6

To find a line that is parallel to \( y = \frac{5}{6}x \) and passes through the point \( (12, 6) \), we first note that parallel lines have the same slope. The slope of the line \( y = \frac{5}{6}x \) is \( \frac{5}{6} \).

Now we can use the point-slope form of the equation of a line, which is given by:

\[ y - y_1 = m(x - x_1) \]

Where:

  • \( m = \frac{5}{6} \) (the slope)
  • \( (x_1, y_1) = (12, 6) \)

Substituting the known values into the point-slope form:

\[ y - 6 = \frac{5}{6}(x - 12) \]

Let's simplify this:

  1. Distribute \( \frac{5}{6} \):

\[ y - 6 = \frac{5}{6}x - \frac{5}{6} \cdot 12 \] \[ y - 6 = \frac{5}{6}x - 10 \]

  1. Add 6 to both sides:

\[ y = \frac{5}{6}x - 10 + 6 \] \[ y = \frac{5}{6}x - 4 \]

Now, we need to check which of the provided options is correct.

The options given are:

  1. \( 6y = 5x \)
  2. \( y = \frac{5}{6}x - 4 \)
  3. \( y = \frac{5}{6}x + 6 \)
  4. \( y = -\frac{6}{5}x + 6 \)

The line that matches our result \( y = \frac{5}{6}x - 4 \) is:

\( y = \frac{5}{6}x - 4 \).

Which of the following options would be the equation of a line perpendicular to the line y=−3x+5?(1 point)
Responses

y=1/3x+9
y equals Start Fraction 1 over 3 End Fraction x plus 9

y=−1/3x+9
y equals negative Start Fraction 1 over 3 End Fraction x plus 9

y=3x+9
y equals 3 x plus 9

y=−3x+9

To find the equation of a line that is perpendicular to the line given by \( y = -3x + 5 \), we first need to determine the slope of the original line.

  1. Identify the slope of the original line:
    The slope (\( m \)) of the line \( y = -3x + 5 \) is -3.

  2. Find the slope of the perpendicular line:
    The slope of a line that is perpendicular to another is the negative reciprocal of the original slope.
    The negative reciprocal of \(-3\) is: \[ m = \frac{1}{3} \]

Now, let's look at the provided options and identify the one with the slope of \(\frac{1}{3}\):

  1. \( y = \frac{1}{3}x + 9 \): Slope is \(\frac{1}{3}\) (this could be our answer).
  2. \( y = -\frac{1}{3}x + 9 \): Slope is \(-\frac{1}{3}\).
  3. \( y = 3x + 9 \): Slope is \(3\).
  4. \( y = -3x + 9 \): Slope is \(-3\).

The only line with a slope of \(\frac{1}{3}\) is:

\( y = \frac{1}{3}x + 9 \).

Thus, the answer is \( y = \frac{1}{3}x + 9 \), which is the equation of the line perpendicular to \( y = -3x + 5 \).

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