Find the equation of the line tangent to f(x)=3x^2-2x-1 at the point where x=2

Answer 1

the slope of the tangent line at any point (x,f(x)) is 6x-2

f(2) = 7

So, at (2,7) the slope is 10

now you have a point and a slope, so the tangent line is

y-7 = 10(x-2)