Find the equation of the ellipse with vertices at (-1,3) and (5,3)and length of minor 4.

Answer 1

first find the centre, which would be the midpoint of the vertices,
it would be (2,3)
the length of the minor axis is 4, so b = 2

sofar we would would have
(x-2)^2/a^2 + (y-3)^2/4 = 1
but (5,3) lies on it, so
(5-2)^2/a^2 + (3-3)^2/4 = 1
9/a^2 = 1
a^2 = 9

final equation
(x-2)^2/9 + (y-3)^2/4 = 1

Answer 2

thanks!

Answer 3

8(16)