To find the equation of the axis of symmetry, we can use the formula x = -b/(2a) for a quadratic function in the form y = ax^2 + bx + c.
Given the function y = x^2 - 10x - 4, we have a = 1 and b = -10. Plugging these values into the formula, we get:
x = -(-10)/(2*1)
x = 10/2
x = 5
Therefore, the equation of the axis of symmetry is x = 5.
Find the equation of the axis of symmetry and the coordinates of the vertex of the graph of the following function.
y equals x squared minus 10 x minus 4
Question content area bottom
Part 1
What is the equation of the axis of symmetry?
enter your response here (Type an equation. Simplify your answer.)
3 answers
Find the equation of the axis of symmetry and the coordinates of the vertex of the graph of the following function.
y equals x squared minus 10 x minus 4
Question content area bottom
Part 1
What is the equation of the axis of symmetry?
x equals 5 (Type an equation. Simplify your answer.)
Part 2
The vertex is
enter your response here. (Type an ordered pair.)
y equals x squared minus 10 x minus 4
Question content area bottom
Part 1
What is the equation of the axis of symmetry?
x equals 5 (Type an equation. Simplify your answer.)
Part 2
The vertex is
enter your response here. (Type an ordered pair.)
To find the coordinates of the vertex, we substitute the x-coordinate of the axis of symmetry into the function to find the y-coordinate.
When x = 5:
y = 5^2 - 10(5) - 4
y = 25 - 50 - 4
y = -29
Therefore, the coordinates of the vertex are (5, -29).
When x = 5:
y = 5^2 - 10(5) - 4
y = 25 - 50 - 4
y = -29
Therefore, the coordinates of the vertex are (5, -29).