Asked by selina

find the equation of tangent line to the graph of f(x)=xcosx(√2 x) at a=0
Answered by selina
sorry the question is f(x)=xcos(√2 x) at a=0
Answered by Steve
well,
f'(x) = cos(√2 x) - √2 x sin(√2 x)
Not sure what a has to do with things, but if you meant x=0, then
f(0) = 0
f'(0) = 1

So, you want the line with slope 1, which passes through (0,0).

No too much of a challenge there, eh?
Answered by selina
yep thanks
Answered by selina
it will be y=x but how do we know it passes through (0,0)
Answered by Steve
Because y(0) = 0. It helps if you actually read what I write. Or maybe it has something to do with the mysterious "a".
Answered by selina
okay I get it and a is as you said just to say x
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