Asked by Christopher

Find the equation of a line which passes through point P(10, 12) and // to y=x/2 + 4

Answers

Answered by Reiny
since it is parallel to y=x/2 + 4
it will differ only in the y-intercept, so let

y=x/2 + b
plug in the point(10,12)
12 = 5+b
b = 7

y = x/2 + 7
Answered by Steve
or, you can avoid b altogether and go straight to the point-slope form of the line with slope 1/2:

y-12 = 1/2 (x-10)
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