find the equation of a line that is perpendicular to the line y=1/6x+7 and contains the point (-5,0)

Question

y=
(Type your answer in slope intercept form)

Answer 1

slope has to be -6 because it is -1/(1/6)
note m' = -1/m

so of form
y = -6 x + b
put the point in
0 = -6 (-5) + b
so
b = -30
then
y = -6 x -30