g = x -.5 x + 4
did you mean x^2 maybe? or what?
find the equation for the tangent line
g(x)=x-1/2x+4 at x=-1
5 answers
x-1÷2x+4
g = (x-1)/(2x+4)
dg/dx = [(2x+4)-2(x-1)]/(2x+4)^2
at x = -1
dg/dx = m the slope
= [(-2+4)-2(-2)]/(2)^2
= 6/4 = 3/2
and
g = -2/2 = -1
so
y = m x + b
-1 = 3/2 (-1) + b
b = 1/2
so
y = (3/2) x + 1/2
or 2 y = 3 x + 1
check my arithmetic!
dg/dx = [(2x+4)-2(x-1)]/(2x+4)^2
at x = -1
dg/dx = m the slope
= [(-2+4)-2(-2)]/(2)^2
= 6/4 = 3/2
and
g = -2/2 = -1
so
y = m x + b
-1 = 3/2 (-1) + b
b = 1/2
so
y = (3/2) x + 1/2
or 2 y = 3 x + 1
check my arithmetic!
perfect ty! i got y=3/2x+1/2
Good :)
2 answers