The focus is (14,0) and the directrix is x=0
SO, you have a parabola opening to the right, with 2p=14, and vertex at (7,0) halfway from directrix to focus:
y^2 = 28(x-7)
http://www.wolframalpha.com/input/?i=parabola+y%5E2+%3D+28(x-7)
Find the equation for the graph of the path of a point P(x,y) that moves such that P(x,y) is the same distance from the point (14,0) and the y-axis.
1 answer