Find the equation and sketch the parabola that has vertex V (-1; 0) and focus F(-4; 0).

Answer 1

The distance between the vertex and the focus is 3
so the directrix must be x =2 (from -1 to 2 is 3)

let (x,y) be any point on our parabola

√( (x+4)^2 + y^2) = √( (x-2)^2 + 0)
square both sides and expand

x^2 + 8x + 16 + y^2 = x^2 - 4x + 4
y^2 = -12x - 12