Find the dy/dx for each of the following

Question

1)y=ln(2x^6-15)
2)y= 3√ 2x^2-3x-1/5
3) y= x^4/x^2+1

Answer 1

1. dy/dx = 12x^5 /(2x^6 - 15) ---- routine

2. dy/dx = 6√2 x - 3 ---- routine

3. the way you typed it,
y = x^4/x^2 + 1
y = x^2 + 1
dy/dx = 2x

if you meant x^4/(x^2+ 1) , then you would use the quotient rule. See how critical it is to use brackets ?

Answer 2

there is no brackets for question 3. Although i am still confused. would you be able to give step by step solutions?