Find the domain and range.

​f(x)equalsxsquaredplus2

1 answer

To find the domain and range of the function \( f(x) = x^2 + 2 \), we'll analyze each aspect separately.

Domain:

The domain of a function consists of all the possible input values (x-values) for which the function is defined.

For the function \( f(x) = x^2 + 2 \):

  • The expression \( x^2 \) is defined for all real numbers.
  • Since there are no restrictions (like square roots of negative numbers or division by zero), the domain is all real numbers.

Domain: \( (-\infty, \infty) \)

Range:

The range of a function is the set of all possible output values (y-values) when we apply the function to its domain.

For \( f(x) = x^2 + 2 \):

  • The term \( x^2 \) reaches its minimum value at \( x = 0\), which is \( 0 \).
  • Thus, the minimum value of \( f(x) \) is \( 0 + 2 = 2 \).
  • As \( x \) increases or decreases without bound (goes to positive or negative infinity), \( x^2 \) increases without bound, and therefore \( f(x) \) also increases without bound.

Thus, the lowest value of \( f(x) \) is \( 2 \), and it can go up to infinity.

Range: \( [2, \infty) \)

Summary:

  • Domain: \( (-\infty, \infty) \)
  • Range: \( [2, \infty) \)
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