Find the distance, in feet, a particle travels in its first 4 seconds of travel, if it moves according to the velocity equation v(t)= −t2 + 4 (in feet/sec).

Answer 1

s(t) = ∫ v(t) dt
= ∫ 4-t^2 dt
= 4t - 1/3 t^3 + C
Since s(0) = 0, C=0, and

s(t) = 4t - 1/3 t^3

Answer 2

Steve you honestly suck