first place is to check your text for some kind of distance formula.
Next, get out some graph paper and plot the two points, then draw a line between them. Call them A and B, respectively.
Now draw a horizontal line from A and a vertical line from B. Where the two lines intersect, call that point C.
Now you have a right triangle, with the right angle at C, and the hypotenuse is AB.
Now recall your Pythagorean Theorem, which says that if the two legs of a right triangle are a and b, and the hypotenuse is c, then
c^2 = a^2+b^2
That is also your distance formula, where
a = x2-x1 = (-40-0)
b = y2-y1 = (0-9)
So, c^2 = 40^2+9^2 = 1609
c = √1609 = 40.11
If you look carefully at the distance formula
d = √(x2-x1)^2 + (y2-y1)^2)
you see that it's really just the Pythagorean Theorem in the context of coordinates, rather than side lengths.
find the distance between (0,9)(-40,0) answer in simplest form id ont know where to start
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