Find the discriminant of the quadratic equation and give the number and type of solutions of the equation.

s^2√5 + s + √5 = 0

I'm confused because of the radical...

1 answer

I would have written it as

√5 s^2 + s = √5 = 0 , so it wouldn't be confused with s^(2√5) + s +so it wouldn't be confused with s^(2√5)5 = 0
That would be a mess

a = √5, b=1 , c=√5

b^2 - 4ac
= 5 - 4(1)√5
= 5 - 4√5