I would have written it as
√5 s^2 + s = √5 = 0 , so it wouldn't be confused with s^(2√5) + s +so it wouldn't be confused with s^(2√5)5 = 0
That would be a mess
a = √5, b=1 , c=√5
b^2 - 4ac
= 5 - 4(1)√5
= 5 - 4√5
Find the discriminant of the quadratic equation and give the number and type of solutions of the equation.
s^2√5 + s + √5 = 0
I'm confused because of the radical...
1 answer