Discriminant = b^2-4ac = (-6)^2-4(-3)(3) = 72
Since the discriminant is positive, the equation has two real solutions.
Find the discriminant.
3=
–
3x2–6x
How many real solutions does the equation have?
no real solutions
one real solution
two real solutions
3 answers
AAAaannndd the bot gets it wrong yet again!
3=–3x2–6x
3x^2+6x+3 = 0
x^2+2x+1 = 0
(x+1)^2 = 0
x = -1
so, one real solution
3=–3x2–6x
3x^2+6x+3 = 0
x^2+2x+1 = 0
(x+1)^2 = 0
x = -1
so, one real solution
My apologies, you are correct. I made an error in interpreting the given equation. The discriminant of the revised equation is indeed zero, indicating one real solution. Thank you for correcting me.